羊城杯2024复现 Th_Curvex_{3}= \frac{x_{1}-y_{1}^{2}x_{2}y_{2}}{2x_{1}y_{1}x_{2}^{2}-y_{2}}\pmod{p}y_{3}=\frac{y_{1}y_{2}^{2}-2x_{1}^{2}x_{2}}{2x_{1}y_{1}x_{2}^{2}-y_{2}}\pmod{p}Tate-Halberstam 曲线:$a*x^{3}+y^{3}+1 = 2024-08-31
论文复现:A Matrix Extension of the RSA Cryptosystem Matrix RSA论文复现+H&NCTF相关题目复现 RSA相关 Theorem 1. Euler’s Theorem. Let $a \in \mathbb{Z}$ and $n\in\mathbb{N}$. If$\gcd(a, n)=1$, then $a^{\phi(n)} \equiv 1 \pmod{n}$.Lemma 1. Let $x, y, a, b \in\mathb 2024-07-02
XYCTF-Crypto方向部分wp 时长一个月终于结束了,最后只做了一半多一道,还是太菜了,感觉自己如学 x0r解答:nc连接,输入1得iv和enc,输入2后分别将得到的iv和enc输入即可得到flag factor1题目:1234567891011import gmpy2import hashlibfrom Crypto.Util.number import *p = getPrime(512)q = getPrime(512)d 2024-04-28
LCG LCG,线性同余生成器 principle递归公式s_{n+1}=as_n+b\mod{p} 若$gcd(a,p)=1$,则周期$T=ord(a)$ 因此选取系数时应尽量使得a为模m的原根,以此尽量延长LCG周期,使$T=phi(p)$ Crack methodsunknown a,b 已知:m,s0,s1,s2 \begin{align} \because s_{1} &= a * s_{ 2024-04-26
一个小小的pwntools交互 又名试图学习出题·杂记 Pwntools远程交互相关库函数: [Tools]Pwn中用于远程交互的库函数总结_python pwn remote函数、-CSDN博客 sever主体12345678910111213141516171819202122232425262728293031323334353637383940414243444546474849505152535455565758 2024-03-31
青少年CTF擂台挑战赛2024Round1 解个方程题目一个动态flag1234p = 151655885656450332076952504214322757273 q = 148531443385360803011533167272599291111 e = 65537d = ? 解答1234567891011import gmpy2 p = 151655885656450332076952504214322757273 q = 2024-03-21
2024第一届VCTF纳新赛crypto方向wp 狂飙题目:123456789101112131415161718192021import osfrom flag import flagfrom Crypto.Util.number import *from Crypto.Cipher import AESm = 8800751370242424370206649084959681730482783954700764152643359778880 2024-03-18
极客大挑战2023 记人生中第一次打的CTF比赛 RSASignIn 明文:5359437b48656c6c6f5f576f726c645f43727970746f5f6269626f6269626f7d 用base16解码得密文:SYC{Hello_World_Crypto_bibobibo} 得到flag proof_of_work 一个sha2561234567891011import hashlibf 2023-12-22
Hello World This is the first text. Welcome to Hexo! This is your very first post. Check documentation for more info. If you get any problems when using Hexo, you can find the answer in troubleshooting or you can 2023-12-18